CALENDER:

CALENDER:

Points to be remember :

Year= 365

Leap year= 366 which is divided by 4

For century year eg:2000, 100,200 year means we should divide both by 4 & 40 (then only we can say it as leap year

No of odd days present in a months

jan -3odd days

feb- 0odd day (for non leap year) & 1 odd day ( leap years)

mar- 3

apri – 2

may-3

jun-2

july-3

aug-3

sept-2

oct-3

nov-2

dec-3

 Ø  Ordinary year has 1 odd day

 Ø  Leap year has 2 odd days

 Ø  For 100 years 5 odd days will their : because 100/4= 24 leap year & 100-24=76 ordinary year . inorder to find the odd days we have to multiply the leap years *2=48+76(ord year)=124 will come now divide this 124/7= u will get rem as 5 ie is odd day present in a year

 Ø  Similarly for 200year= 3 odd days

 Ø  300years=1 odd days

 Ø  400 year = 0 odd days

 Ø  Similar order will continue( so its better to memorize this odd days for 1^st 400 years)  

 Ø  For  every  400 century  year is called as leap year ie400,800,1200.....

s__________________________________________________________________________________

Now example:

1)    Find out which day is 23/9/2012?

                 Solution:

Split 2012 = 2000 + 11 (for 2012 we have to put it as 11 only) rule ( always split the year into multiple of 4 or 400  because u can directly substitute the value as 0 odd days

For 2000=0 odd days we know that already

Now for 11 : with in 11 years we knw 2 leap year and 9 ordinary year will come

Multiply the leap year into 2

Soè  11+ (2*2)+ {date (upto 9 th month calculate odd days 3(for jan)+1(since2012 leap year)+3+23+3+2+3+3+(23 given date of month/7)== 22/7=1 as rem}

11+4+1=14

14/7=0 rem(ans)

0-sun

1-mon

2- Tuesday

3- wed

4- Thursday

5- fri

6- sat

So 23/9/2012 is Sunday

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2.which day is 25/3/1992?

Sol: 1600+391+25^th mar

We know that for 1600 (0 odd days)

We can also split 391 as =300+91

For 300^th century( mentioned above) we know as 1

So è 0+1+91+25mar

91/4= 22(quo)à leap year(22*2)

91-22= 69à ordinary year

Soè 0+1+44+69+25^th mar

25/7=4 rem

0+1+44+69+date{ upto mar calculate odd day 3+1(since 92 leap year)+(25/7è4)}

0+1+44+69+{3+1+4}

0+1+44+69+8=122/7=3 rem

0 mean sun

1 – mon

2- tue

3 – wed (ans)

_________________________________________________________________________________Model 2:

25/3/1992=> wed

Find 24/3/2012=>????

Sol:

For 93( 1 odd day since it is ordinary year)

Lly

94(1)+95(1)+96(2 since it is leap year)+97(1)+98(1)+99(1)+2000(2)+1+1+1+2+1+1+1+2+1+1+1+2=25/7è 4 rem

Now we have take 0 as the day given in the question ie 0-wed 

            0-      Wed

            1-      Thr

            2-      Fri

            3  -      Sat

4-      Sun ( we calculate upto 25 th of mar 2012 but they asked for 24^th so ans is Saturday  

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Model- 3

1.       The calendar of the year  2007 will be same as ?

a)      2014  b)2016 c) 2012 d) 2018

To solve this kind of question we have to calculate upto the years given in the options

Year	2007	08	09	10	11	12	13	14	15	16	17	18
Odd day	1	2	1	1	1	2	1	1	1	2	1	1
Sum	1	3	4	5	6	8	9	10	11	13	14	15

  Option a) 2014 è Sum is 10 ( not a multiple of 7)

 Option b) 2016 -> sum is 13 not a multiple of 7

Option c ) 2017à sum is 14 multiple of 7 ( so next year of 2017 ie 2018 will be the ans for this question

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